Evaluate
cos a cos 2a cos 3a..........cos 999a, where a = 
Text Solution
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cos a cos 2a cos 3a..........cos 999a, a = 
Let P denotes the desired product, and let
Q = sin a sin 2a sin 3a.......sin 999a.
Then
2 999 PQ = (2 sin a cos a)(2 sin 2a cos 2a).........(2 sin 999a cos 999a)
= sin 2a sin 4a .....sin 1998a
= (sin 2a sin 4a ........sin 998a) [–sin(2 π – 1000a)]. [–sin(2 π – 1002a)]........[–sin(2 π – 1998a)]
= sin 2a sin 4a ........sin 998a sin 999a sin 997a .......sin a = Q
It is easy to see that Q ≠ 0. Hence the desired product is P =
.
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